SOLVED

19.2 Algorithmic Questions 1) In which of the following processes does the substance become more orderly? A) water freezing B) ice melting C) water evaporating D) salt dissolving in water E) dry ice subliming 2) Identify the change in state that does not have an increase in entropy. A) gasoline freezing B) water boiling C) ice melting D) dry ice subliming E) water evaporating 3) Which of the following processes have a ΔS > 0? A) 2 NH3(g) + CO2(g) → NH2CONH2(aq) + H2O(l) B) lithium fluoride forms from its elements C) 2 HI(g) → H2(g) + I2(l) D) lithium chloride dissolves in pure water E) All of the above processes have a DS > 0. 4) Which of the following processes have a ΔS < 0? A) water freezes B) isopropyl alcohol condenses C) ethanol (g, at 555 K) → ethanol (g, at 400 K) D) carbon dioxide(g) → carbon dioxide(s) E) All of the above processes have a ΔS < 0. 5) Which of the following processes shows a decrease in entropy of the system? A) 2 NO(g) + O2(g) → 2 NO2(g) B) COCl2(g) → CO(g) + Cl2(g) C) CH3OH(l) → CO(g) + 2H2(g) D) NaClO3(s) →Na+(aq) + ClO3-(aq) E) None of the above will show a decrease in entropy. 6) Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N2(g) + 2 O2(g) → 2 NO2(g)ΔH = +66.4 kJ A) ΔSsurr = +223 J/K, reaction is not spontaneousnot spontaneous B) ΔSsurr = -223 J/K, reaction is not spontaneous C) ΔSsurr = -2656 J/K, reaction is spontaneous D) ΔSsurr = +66.4 kJ/K, reaction is not spontaneous E) ΔSsurr = -66.4 J/K, it is not possible to predict the spontaneity of this reaction without more information. 7) Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whether or not this reaction will be spontaneous at this temperature. 2 NO(g) + O2(g) → 2 NO2(g)ΔH = -114 kJ A) ΔSsurr = +114 kJ/K, reaction is spontaneous B) ΔSsurr = +114 kJ/K, reaction is not spontaneous C) ΔSsurr = +321 J/K, reaction is spontaneous D) ΔSsurr = -321 J/K, reaction is not spontaneous E) ΔSsurr = +321 J/K, it is not possible to predict the spontaneity of this reaction without more information. 8) Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 398 K. Predict whether or not this reaction will be spontaneous at this temperature. 4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(g)ΔH = -1267 kJ A) ΔSsurr = +12.67 kJ/K, reaction is spontaneous B) ΔSsurr = -12.67 kJ/K, reaction is spontaneous C) ΔSsurr = +50.4 kJ/K, reaction is spontaneous D) ΔSsurr = +3.18 kJ/K, reaction is spontaneous E) ΔSsurr = -3.18 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. 9) Place the following in order of increasing molar entropy at 298 K. CO2C10H22CO A) CO2 < C10H22 < CO B) C10H22 < CO2 < CO C) CO < CO2 < C10H22 D) C10H22 < CO < CO2 E) CO2 < CO < C10H22 10) Place the following in order of decreasing molar entropy at 298 K. HClN2H4He A) He > N2H4 > HCl B) He > HCl > N2H4 C) N2H4 > He > HCl D) N2H4 > HCl > He E) HCl > N2H4 > He